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Old 07-26-2006, 11:05 PM   #1
Registered: Feb 2006
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How to issue "ls" command start with the largest file size in a folder?


How do I use the command "ls" to display the largest file size in a folder?
Old 07-26-2006, 11:16 PM   #2
Registered: Jul 2006
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the most i could come up with is ls -s which gives you the size of all the files. i got this in the man pages

[matt@cpe-69-133-112-109 sounds]$ ls -s
total 80
48 turnmeon.wav    32

man ls

Last edited by AmphetaminePhreak; 07-26-2006 at 11:19 PM.
Old 07-26-2006, 11:21 PM   #3
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sort by size largest first
ls -S
Old 07-26-2006, 11:40 PM   #4
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I would be inclined to use ls -lrS, which gives a long listing, sorted by size, with the largest last in the list (and therefore not scrolled off the screen).
Old 07-27-2006, 12:58 AM   #5
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ls -sSr and ls -sS are both also useful.
Old 07-27-2006, 04:28 AM   #6
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hello fjkum. i guess you can also use du for that.

smallest first (recursive)
du * | sort -n
largest first (recursive)
du * | sort -nr
smallest first (not recursive)
du * -s | sort -n
largest first (not recursive)
du * -s | sort -nr
you can remove the numbers by adding '| cut -f 2'
du * -s | sort -nr | cut -f 2
by default the sizes are printed in kilobytes. add '-b' to du to print sizes in bytes.
du * -s -b | sort -nr

Last edited by konsolebox; 07-27-2006 at 04:29 AM.


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