LinuxQuestions.org - How to issue "ls" command start with the largest file size in a folder?

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fjkum

07-26-2006 10:05 PM

How to issue "ls" command start with the largest file size in a folder?

Hi,

How do I use the command "ls" to display the largest file size in a folder?

AmphetaminePhreak

07-26-2006 10:16 PM

the most i could come up with is ls -s which gives you the size of all the files. i got this in the man pages

Code:

[matt@cpe-69-133-112-109 sounds]$ ls -s

total 80

48 turnmeon.wav    32 turnmeon.zip



man ls

AAnarchYY

07-26-2006 10:21 PM

sort by size largest first

Code:

ls -S

bartonski

07-26-2006 10:40 PM

I would be inclined to use ls -lrS, which gives a long listing, sorted by size, with the largest last in the list (and therefore not scrolled off the screen).

Matir

07-26-2006 11:58 PM

ls -sSr and ls -sS are both also useful.

konsolebox

07-27-2006 03:28 AM

hello fjkum. i guess you can also use du for that.

smallest first (recursive)

Code:

du * | sort -n

largest first (recursive)

Code:

du * | sort -nr

smallest first (not recursive)

Code:

du * -s | sort -n

largest first (not recursive)

Code:

du * -s | sort -nr

you can remove the numbers by adding '| cut -f 2'

Code:

du * -s | sort -nr | cut -f 2

by default the sizes are printed in kilobytes. add '-b' to du to print sizes in bytes.

Code:

du * -s -b | sort -nr

regards :)

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