What's your kernel size?

Ygrex · 12-05-2009, 01:04 PM

Unlike previous threads (2005 and 2004), please, note the total kernel size (or sizes

). I think, desktop-oriented only stations should be presented here

Firstly, disk usage:

Code:

# LC_MESSAGES=C du -shc /boot/vmlinuz-2.6.32 /boot/initramfs-2.6.32 /lib/modules/2.6.32
1,3M    /boot/vmlinuz-2.6.32
3,3M    /boot/initramfs-2.6.32
9,6M    /lib/modules/2.6.32
15M     total

OK, my kernel consumes 15Mb on the HDD

Secondly, tipical number of loaded modules:
Code:
```
# wc -l /proc/modules
75 /proc/modules
```
therefore, mostly I use 75 modules
The number of loaded modules can be compared to the total compiled modules number:
Code:
```
$ find /lib/modules/2.6.32/ -name '*.ko' | wc -l
315
```
I have 315 modules ready to work

And the last point is a RAM usage. I am not sure how to measure it precisely, but I've summarized these ranges:

Code:

$ cat /proc/iomem | grep -wi kernel
  01000000-011fc069 : Kernel code
  011fc06a-012b64e7 : Kernel data
  012f5000-01317493 : Kernel bss

a little bash-trick to calculate it:

Code:

$ echo $(( $(cat /proc/iomem | grep -wi kernel | sed -r 's#^\s*([0-9a-f]+)-([0-9a-f]+)\s+:.*$#0x\2 - 0x\1 +#') 0 ))
2984313

it seems like a truth, so my kernel is 2.84Mb in RAM

Then, how fat is your kernel?

jhwilliams · 12-05-2009, 02:57 PM

I'll play.

Kernel size on disk:

Code:

du -hsc /boot/vmlinuz-2.6.31-15-generic /boot/initrd.img-2.6.31-15-generic /lib/modules/2.6.31-15-generic/
3.8M	/boot/vmlinuz-2.6.31-15-generic
7.8M	/boot/initrd.img-2.6.31-15-generic
98M	/lib/modules/2.6.31-15-generic/
110M	total

Loaded modules:

Code:

lsmod | wc -l
77

Available modules:

Code:

find /lib/modules/2.6.31-15-generic/ -name "*.ko" | wc -l
2472

alunduil · 12-05-2009, 03:04 PM

This ought to be fun.

Kernel Size on Disk:

Code:

du -hsc /boot/bzImage-2.6.32-gentoo /boot/config-2.6.32-gentoo /boot/System.map-2.6.32-gentoo
2.6M    /boot/bzImage-2.6.32-gentoo
58K     /boot/config-2.6.32-gentoo
1.6M    /boot/System.map-2.6.32-gentoo
4.2M    total

Loaded Modules:

Code:

lsmod | wc -l
26

Available Modules:

Code:

find /lib/modules/2.6.32-gentoo/ -name "*.ko" | wc -l
42

Regards,

Alunduil

MrCode · 12-05-2009, 05:42 PM

I'm such a sucker/n00b/(insert insulting name here)...

Code:

mrcode@linuxbox:~$ find /lib/modules/2.6.28-16-generic -name "*.ko" | wc -l
2315
mrcode@linuxbox:~$ lsmod | wc -l
64

Any way to know which ones I actually need? 64 loaded modules is a bit *ridiculous*, isn't it?

And regarding the available modules...

Didn't know I had so much bloat...

XavierP · 12-05-2009, 06:01 PM

Kernel Size on Disk

Code:

3.8M    /boot/vmlinuz-2.6.31-16-generic
81M     /lib/modules/2.6.31-16-generic
84M     total

Loaded Modules

Code:

52 /proc/modules

Loaded v Compiled

Code:

find /lib/modules/2.6.31-16-generic/ -name '*.ko' | wc -l
2665

RAM usage

Code:

cat /proc/iomem | grep -wi kernel
  00100000-00575b93 : Kernel code
  00575b94-0078d3c7 : Kernel data
  0081a000-008a809f : Kernel bss

+ Bash calculation

Code:

echo $(( $(cat /proc/iomem | grep -wi kernel | sed -r 's#^\s*([0-9a-f]+)-([0-9a-f]+)\s+:.*$#0x\2 - 0x\1 +#') 0 ))

7451749

This is using Kubuntu Karmic Koala (v9.10), so it may be a bit bloaty...

MrCode · 12-05-2009, 06:09 PM

Quote:

Originally Posted by XavierP

Loaded Modules

Code:

52 /proc/modules

Loaded v Compiled

Code:

find /lib/modules/2.6.31-16-generic/ -name '*.ko' | wc -l
2665

Okay, so I guess I shouldn't put myself down so much...apparently it's Ubuntu's fault, not mine (I'm running 9.04 Jaunty, btw).

And what horrible gibberish is this?

Quote:

Code:

sed -r 's#^\s*([0-9a-f]+)-([0-9a-f]+)\s+:.*$#0x\2 - 0x\1 +#') 0 ))

I can kind of make out what you did, but that syntax is still like reading Chinese to me...then again, I'm still a n00b, so I guess I shouldn't really care (for now).

Ygrex · 12-06-2009, 02:27 AM

Quote:

Originally Posted by MrCode

it's Ubuntu's fault, not mine (I'm running 9.04 Jaunty, btw).

it's OK for precompiled kernels, for they must be universal and run on any machine

Quote:

Originally Posted by MrCode

I can kind of make out what you did, but that syntax is still like reading Chinese to me...

it does nothing more than filters content of /proc/iomem and composes an arithmetic expression for bash; nothing horrible! (here's a chapter about "Chinese" itself)

Thanks to anyone! I hope we'll see abit more results here

H_TeXMeX_H · 12-06-2009, 07:04 AM

Code:

bash-3.1$ du -shc /boot/vmlinuz /lib/modules/2.6.29.6
2.1M	/boot/vmlinuz
46M	/lib/modules/2.6.29.6
48M	total
bash-3.1$ wc -l /proc/modules
58 /proc/modules
bash-3.1$ find /lib/modules/2.6.29.6 -name '*.ko' | wc -l
1049
bash-3.1$ echo $(( $(cat /proc/iomem | grep -wi kernel | sed -r 's#^\s*([0-9a-f]+)-([0-9a-f]+)\s+:.*$#0x\2 - 0x\1 +#') 0 ))
4670901

mlangdn · 12-06-2009, 07:14 AM

I'll give this a go as well on my custom kernel.

Code:

# LC_MESSAGES=C du -shc /boot/vmlinuz-2.6.31.1 /boot/initramfs-2.6.31.1 /lib/modules/2.6.31.1
2.1M    /boot/vmlinuz-2.6.31.1
du: cannot access `/boot/initramfs-2.6.31.1': No such file or directory
20M     /lib/modules/2.6.31.1
22M     total

Code:

wc -l /proc/modules
50 /proc/modules

Code:

find /lib/modules/2.6.31.1/ -name '*.ko' | wc -l
190

Code:

cat /proc/iomem | grep -wi kernel
  01000000-0131f590 : Kernel code
  0131f591-0146dc57 : Kernel data
  014ea000-0151f487 : Kernel bss

Code:

echo $(( $(cat /proc/iomem | grep -wi kernel | sed -r 's#^\s*([0-9a-f]+)-([0-9a-f]+)\s+:.*$#0x\2 - 0x\1 +#') 0 ))
4862173