gets fuction gives warning, why?

sharapchi · 11-01-2005, 04:19 AM

Hi,
I am a new programmer on linux. I wrote a short code for testing but gets function gives warning. I was using slackware 10.1 and gcc in 10.1 does not gives warning like this. I am using slackware 10.2 now and gcc 3.3.6 gives it. There is the code and output which gcc gives.

-----------------------

#include <stdio.h>

#define SIZE 100

int main()
{
char str[SIZE];
int k;
int len = 0;

printf("Input a string : ");
gets(str);
printf("String = (%s)\n", str);

for (k = 0; str[k] != '\0'; ++k)
len++;

printf("(%s) = %d\n", str, len);

return 0;
}

----------------------

bash-3.00$ gcc 042_len.c
/tmp/ccU1hwx4.o(.text+0x32): In function `main':
: warning: the `gets' function is dangerous and should not be used.
bash-3.00$

-----------------------

Alien Bob · 11-01-2005, 04:41 AM

http://home.att.net/~jackklein/ctips01.html#safe_gets

Eric

sharapchi · 11-01-2005, 08:43 AM

Thanks but i want to use gets also using that is so dangerous. How can i turn off warnings of gcc?

gbonvehi · 11-01-2005, 08:59 AM

Ok.. let's see: man gcc

Quote:

You can request many specific warnings with options beginning -W, for example -Wimplicit
to request warnings on implicit declarations. Each of these specific warning options
also has a negative form beginning -Wno- to turn off warnings; for example,
-Wno-implicit. This manual lists only one of the two forms, whichever is not the
default.

-w Inhibit all warning messages.

keefaz · 11-01-2005, 10:31 AM

Why not use :

Code:

fgets(str, SIZE, stdin);