[SOLVED] awk: how to print a field when field position is unknown?
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awk: how to print a field when field position is unknown?
I'm trying to display fields from flat files where the first 8 fields are always the same. Fields 9 - n are varied but will contain specific patterns I'm after. I'm using this so far because "mySearch" is on each line I want to examine.
doh! I was at least on the right track with %s. I would've been spinning my wheels a long time though because I didn't realize it needed multiples. Also, there was a comma missing from the 2nd printf of your example... now works perfect for me here. And I learned a lot - Thank you!
I've discovered that /mySearch/ is a variant of alpha case per each line. E.g. Thomas or THOMAS.
I've tried the "tolower" function but I don't seem to understand how to make tolower operate on the very first regex in the command. I've searched many examples but they end up being just the basic tolower($1) ~ /foo/ examples.
Can tolower work with that command or is there a better mechanism to bypass case of the pattern I'm trying to match?