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Old 11-08-2003, 03:50 PM   #1
Registered: Jan 2003
Location: Ballston Lake, NY
Distribution: Slackware, Debian
Posts: 660

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Two field seperators in awk??

Need to parse a file with two different field seperators. Here's an example line form the file...

FOSS:05-23-00:Paper,9.95:Game,45.99:Hub,39.95:Patch Cable,29.95

format is name:date:item,price...etc

there can be any # of item,price's at the end

in the beginning of the awk script the field seperator needs to be set to ":" for the main seperation of the fields.... but how can I extract the items and prices based on the "," field seperator??
Old 11-08-2003, 06:12 PM   #2
Registered: Oct 2003
Posts: 66

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Unless I misunderstand what you want:

Extract the field and treat the items separately:
awk -F: '{print $3}' file1 | awk -F, '{print $1, $2}'
Paper 9.95
Old 11-09-2003, 10:12 AM   #3
Registered: Jan 2003
Location: Ballston Lake, NY
Distribution: Slackware, Debian
Posts: 660

Original Poster
Rep: Reputation: 30
Good idea, but I think I figured out what needed to be done.... did a little reading and found the split operator...

for (i=3;i<=NF;i++)
Set i=3 cause thats always the first item,price...
<= to the # of fields so it can get the last value
split $i using "," and add it up to get my total.

Arr[2] being the price and Arr[1] being the item...



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