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Old 10-29-2007, 02:14 PM   #1
dbland07666
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Registered: Oct 2007
Posts: 2

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How to parameterize which field awk should print?


I have a script that runs awk and i want to parameterize which field awk prints. For example, go.sh contains:

#!/bin/bash
echo one two three | awk ' {print $2} '

I want to be able to pass set the field that awk prints at run time, eg, this would tell awk to print the 3rd field:

go.sh 3

I can't figure out how to do this.
 
Old 10-29-2007, 02:23 PM   #2
b0uncer
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Registered: Aug 2003
Distribution: CentOS, OS X
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Would this work, maybe?

Quote:
#!/bin/bash
# $1 is the first argument given; $0 is the script itself

echo one two three | awk ' {print $('$1')} '
Just a wild guess..

EDIT: now that I copypasted it, chmod'ed and ran, it seems it works - for me, at least..

Quote:
$ ./go.sh 1
one
$ ./go.sh 2
two
$ ./go.sh 3
three
Of course you'll want to test if the user gave an argument at all, or if the argument is a number at all, or if it's a sane number..things like that. Or at least write the program so that it's not doing anything nuts.

Last edited by b0uncer; 10-29-2007 at 02:25 PM.
 
Old 10-29-2007, 03:49 PM   #3
dbland07666
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Registered: Oct 2007
Posts: 2

Original Poster
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Thanks -- that's exactly what I wanted

P.S. Is there a way to mark the thread as "answered"
 
  


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