[SOLVED] sed print range to end of file

schneidz · 04-08-2009, 09:36 AM

hi, i would like to know how to print (in this case) from line # 298,147 to the last line of the file:

Code:

sed -n 298147,$p hosp-file
sed: 0602-404 Function 298147, cannot be parsed.

thanks,

colucix · 04-08-2009, 09:42 AM

Code:

sed -n '298147,$ p' hosp-file

The single quotes are necessary in this case to protect the $ sign from the shell substitution. Otherwise, you can always use tail:

Code:

tail -n +298147 hosp-file

pixellany · 04-08-2009, 09:51 AM

Quote:

Originally Posted by colucix

Code:

sed -n '298147,$ p' hosp-file

Maybe the single quotes are necessary in this case to protect the $ sign from the shell substitution.[/CODE]

Delete "maybe".....

The sed books say always start with single quotes, and then back off to double-quotes where necessary.

colucix · 04-08-2009, 09:59 AM

Quote:

Originally Posted by pixellany

Delete "maybe".....

The sed books say always start with single quotes, and then back off to double-quotes where necessary.

Maybe deleted... as per your suggestion!

Thanks, pixellany!

pixellany · 04-08-2009, 01:30 PM

At the next Nitpickers Convention, I'll buy you a beer......