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schneidz

04-08-2009 09:36 AM

sed print range to end of file

hi, i would like to know how to print (in this case) from line # 298,147 to the last line of the file:

Code:

sed -n 298147,$p hosp-file

sed: 0602-404 Function 298147, cannot be parsed.

thanks,

colucix

04-08-2009 09:42 AM

Code:

sed -n '298147,$ p' hosp-file

The single quotes are necessary in this case to protect the $ sign from the shell substitution. Otherwise, you can always use tail:

Code:

tail -n +298147 hosp-file

pixellany

04-08-2009 09:51 AM

Quote:

Originally Posted by colucix (Post 3502501)

Code:

sed -n '298147,$ p' hosp-file

Maybe the single quotes are necessary in this case to protect the $ sign from the shell substitution.[/CODE]

Delete "maybe".....;)
The sed books say always start with single quotes, and then back off to double-quotes where necessary.

colucix

04-08-2009 09:59 AM

Quote:

Originally Posted by pixellany (Post 3502513)

Delete "maybe".....;)
The sed books say always start with single quotes, and then back off to double-quotes where necessary.

Maybe deleted... as per your suggestion! ;) Thanks, pixellany!

pixellany

04-08-2009 01:30 PM

At the next Nitpickers Convention, I'll buy you a beer......;)

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