Pyhton Directory List

facets · 06-09-2004, 06:28 AM

Hi Guys,

I'm trying to get a directory listing so I can run a 'regex' over them something like
sed -e 's/*.*_//' -e 's/\..*$//'` but I can't get them to list. All I get back is []

any ideas?
tia, mark.

#!/usr/bin/env python
import os, sys, dircache
pathname = os.path.dirname(sys.argv[0])
print 'full path =', os.path.abspath(pathname)
listfiles=dircache.listdir("pathname")
print listfiles

ranger_nemo · 06-09-2004, 06:42 AM

Your problem is the listfiles=... line. Take the quotes off "pathname". If you have it in quotes, it treats "pathname" as the actual pathname, as if you had typed in something like "/home/facets/dir_that_doesn't_exist". Since it can't find the dir, it returns an empty list. Without the quotes, it will treat pathname as the variable you want it to be.

facets · 06-09-2004, 06:46 AM

#!/usr/bin/env python
import os, sys, dircache, string, re
pathname = os.path.dirname(sys.argv[0])
listfiles=dircache.listdir(pathname)

This returns the same output []
Any ideas?
TIA, Mark.

ranger_nemo · 06-09-2004, 07:51 AM

I copied it straight off, and it works for me...

Code:

$ cat test.py
#!/usr/bin/env python
import os, sys, dircache, string, re
pathname = os.path.dirname(sys.argv[0])
listfiles=dircache.listdir(pathname)

print "First command-line argument = ", sys.argv[0]
print "Path of first argument = ", pathname
print "Files in that path = ", listfiles


$ ./test.py
First command-line argument =  ./test.py
Path of first argument =  .
Files in that path =  ['test.py', 'test.py~']


$ /home/nemo/test/test.py
First command-line argument =  /home/nemo/test/test.py
Path of first argument =  /home/nemo/test
Files in that path =  ['test.py', 'test.py~']

facets · 06-09-2004, 09:24 AM

Yup, your right. Sorry!
I was invoking it with python <scriptname> for some reason.

Cheers, Mark.