[SOLVED] pointer in C language

is noname · 03-22-2010, 11:04 PM

haii ,guyss ..
i am beginner in C language ..please help me .
i see the code :

typedef struct {
int a ;
char *b ;
int *c ;
}EXP2 ;

typedef struct xx {
int a ;
char *s ;
EXP2 *exp2 ;
struct xx *next ;
}EXP1 ;

int main () {
}

paulsm4 · 03-22-2010, 11:12 PM

Hi -

I'm not at all sure what your question is...
... but here's a simple example that might answer at least part of your question(s):

Code:

#include <stdio.h>
#include <string.h>
#include <malloc.h>

typedef struct 
{
  int a ;
  char *b ;
  int *c ;
}
  EXP2;

typedef struct xx 
{
  int a ;
  char *s ;
  EXP2 *exp2 ;
  struct xx *next;
}
  EXP1;

int 
main (int arg ,  char *argv[]) 
{
}#include <stdio.h>
#include <string.h>
#include <malloc.h>

struct x
{
  int a ;
  char *b ;
  int *c ;
};

struct xx 
{
  int a ;
  char *s ;
  struct x *exp2 ;
  struct xx *next;
};

int 
main (int arg ,  char *argv[]) 
{
  struct xx *mystruct = NULL;

  printf ("Allocating data...\n");
  mystruct = calloc (1, sizeof (struct xx));
  printf ("mystruct->a= %d, mystruct->s= %s...\n", mystruct->a, mystruct->s);

  printf ("Populating data...\n");
  mystruct->a = 2;
  mystruct->s = argv[0];
  mystruct->next = mystruct;
  printf ("mystruct->a= %d, mystruct->s= %s...\n", mystruct->a, mystruct->s);
  printf ("mystruct->next->a= %d, mystruct->next->s= %s...\n", 
    mystruct->next->a, mystruct->next->s);

  free (mystruct);
  return 0; 
}

Quote:

Allocating data...
mystruct->a= 0, mystruct->s= (null)...
Populating data...
mystruct->a= 2, mystruct->s= x...
mystruct->next->a= 2, mystruct->next->s= x...
<= I called the program "x", which is why "argv[0]" is "x"...

paulsm4 · 03-23-2010, 09:38 AM

So dude - I'm glad you solved it ... but what were you asking? Twice?

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