cut part of a string using awk

m4rtin · 09-03-2009, 06:24 PM

I have a file full of similar strings, which look like this:

Code:

Port::Ifindex.34
Port::Ifindex.452
Port::Ifindex.3
Port::Ifindex.9999
etc

How to cut everything other than the number after "."?

The output should be

Code:

I don't mind reading myself, but I haven't found any good tutorial about cutting with awk. Or if someone gives an direct answer, then small explanation would be nice or additional examples

kbp · 09-03-2009, 07:07 PM

I dont use awk much, you could use 'cut' though:

Code:

#!/bin/bash

for line in $(cat ./text_file)
do
        echo $line | cut -d. -f2
done

or

Code:

cut -d. -f2 text_file

or for g/awk:

Code:

gawk -F. '{ print $2 }' text_file

cheers,

kbp

ghostdog74 · 09-03-2009, 07:32 PM

Code:

awk -F"." '{print $NF}' file