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m4rtin

09-03-2009 06:24 PM

cut part of a string using awk

I have a file full of similar strings, which look like this:

Code:

Port::Ifindex.34

Port::Ifindex.452

Port::Ifindex.3

Port::Ifindex.9999

etc

How to cut everything other than the number after "."?

The output should be

Code:

I don't mind reading myself, but I haven't found any good tutorial about cutting with awk. Or if someone gives an direct answer, then small explanation would be nice or additional examples ;)

kbp	09-03-2009 07:07 PM

I dont use awk much, you could use 'cut' though:

Code:

#!/bin/bash



for line in $(cat ./text_file)

do

        echo $line | cut -d. -f2

done

Code:

cut -d. -f2 text_file

or for g/awk:

Code:

gawk -F. '{ print $2 }' text_file

cheers,

kbp

ghostdog74

09-03-2009 07:32 PM

Code:

awk -F"." '{print $NF}' file

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