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Old 09-12-2011, 02:58 AM   #1
x201s
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How to remove one of the two similarly named rpm in RHEL


I have two rpms or a package, one 32-bit and the other 64 bit.
I want to delete the 32-bit one while leaving the 64-bit one intact.

I displayed the name of the rpms as follows:
Code:
rpm -qa --queryformat "%{NAME}-%{VERSION}-%{RELEASE}-%{arch}\n"
of the many, my interests are with these two:
libjpeg-6b-37-i386
libjpeg-devel-6b-37-x86_64

Now I tried to delete one as follows:
Code:
rpm -e libjpeg-6b-37-i386
To which, I was promptly told:
Code:
error: package libjpeg-6b-37-i386 is not installed
Why display "libjpeg-6b-37-i386" in the first place, if only to say "not installed" later?
**
When I enquire with "rpm -qa |grep libjpeg", I have the following output:
Code:
libjpeg-6b-37
libjpeg-devel-6b-37
libjpeg-6b-37
Of the two non-devel pacages, one is 32 and the other is 64 bit rpm.

Any pointers, advice, etc. would be helpful.
Thanks for reading.
 
Old 09-12-2011, 03:04 AM   #2
acid_kewpie
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try "rpm -e libjpeg-6b-37.i386"

Annoying isn't it?
 
Old 09-12-2011, 03:08 AM   #3
colucix
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Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.5 OpenSuSE 12.3
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The correct syntax is
Code:
yum remove libjpeg.i386
or
Code:
rpm -e libjpeg.i386
Edit: too late...
 
Old 09-12-2011, 05:57 AM   #4
x201s
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Registered: Dec 2010
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Chris, colucix,
I have smile in my face, a knot-like feeling in my heart.
Smile because there are people who care and the annoying feeling because for me this kind of thing is a show stopper.
Thank you both.
Cheers,
 
  


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