[SOLVED] How to remove one of the two similarly named rpm in RHEL

x201s · 09-12-2011, 02:58 AM

I have two rpms or a package, one 32-bit and the other 64 bit.
I want to delete the 32-bit one while leaving the 64-bit one intact.

I displayed the name of the rpms as follows:

Code:

rpm -qa --queryformat "%{NAME}-%{VERSION}-%{RELEASE}-%{arch}\n"

of the many, my interests are with these two:
libjpeg-6b-37-i386
libjpeg-devel-6b-37-x86_64

Now I tried to delete one as follows:

Code:

rpm -e libjpeg-6b-37-i386

To which, I was promptly told:

Code:

error: package libjpeg-6b-37-i386 is not installed

Why display "libjpeg-6b-37-i386" in the first place, if only to say "not installed" later?
**
When I enquire with "rpm -qa |grep libjpeg", I have the following output:

Code:

libjpeg-6b-37
libjpeg-devel-6b-37
libjpeg-6b-37

Of the two non-devel pacages, one is 32 and the other is 64 bit rpm.

Any pointers, advice, etc. would be helpful.
Thanks for reading.

acid_kewpie · 09-12-2011, 03:04 AM

try "rpm -e libjpeg-6b-37.i386"

Annoying isn't it?

colucix · 09-12-2011, 03:08 AM

The correct syntax is

Code:

yum remove libjpeg.i386

or

Code:

rpm -e libjpeg.i386

Edit: too late...

x201s · 09-12-2011, 05:57 AM

Chris, colucix,
I have smile in my face, a knot-like feeling in my heart.
Smile because there are people who care and the annoying feeling because for me this kind of thing is a show stopper.
Thank you both.
Cheers,