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Old 01-11-2010, 03:04 PM   #1
rhlee
LQ Newbie
 
Registered: Aug 2009
Posts: 11

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Bash for loop


Hi again LQ,

My question arises from trying out something I found in another LQ thread.

I use csplit to split up a large file and I get file xx01, xx02 and so on. I use a for loop to loop through the files.

Code:
for f in "xx**"
do
	echo test
	echo $f
done
Instead of getting

Code:
test xx01 test xx02 test xx03 ...
I get

Code:
test xx01 xx02 xx03 ...
Am I doing something wrong here?


Richard
 
Old 01-11-2010, 03:12 PM   #2
rweaver
Senior Member
 
Registered: Dec 2008
Location: Louisville, OH
Distribution: Debian, CentOS, Slackware, RHEL, Gentoo
Posts: 1,833

Rep: Reputation: 166Reputation: 166
This works for me.

Code:
for f in $(ls xx**); do echo "test $f"; done
 
Old 01-11-2010, 03:17 PM   #3
pixellany
LQ Veteran
 
Registered: Nov 2005
Location: Annapolis, MD
Distribution: Arch/XFCE
Posts: 17,802

Rep: Reputation: 740Reputation: 740Reputation: 740Reputation: 740Reputation: 740Reputation: 740Reputation: 740
It's all in the quotes:
Code:
[mherring@mystical tst]$ ls
xxa  xxb  xxc  xxd
[mherring@mystical tst]$ for fil in *;do echo "test";echo $fil;done
test
xxa
test
xxb
test
xxc
test
xxd
[mherring@mystical tst]$ for fil in "*";do echo "test";echo $fil;done
test
xxa xxb xxc xxd
[mherring@mystical tst]$
 
Old 01-12-2010, 04:59 AM   #4
rhlee
LQ Newbie
 
Registered: Aug 2009
Posts: 11

Original Poster
Rep: Reputation: 0
Quote:
Originally Posted by pixellany View Post
It's all in the quotes
Yes it is, thank you.

It works now.
 
  


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