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rhlee 01-11-2010 02:04 PM
Bash for loop
 
Hi again LQ,

My question arises from trying out something I found in another LQ thread.

I use csplit to split up a large file and I get file xx01, xx02 and so on. I use a for loop to loop through the files.

Code:
for f in "xx**"
do
        echo test
        echo $f
done
Instead of getting

Code:
test xx01 test xx02 test xx03 ...
I get

Code:
test xx01 xx02 xx03 ...
Am I doing something wrong here?


Richard

rweaver 01-11-2010 02:12 PM
This works for me.

Code:
for f in $(ls xx**); do echo "test $f"; done

pixellany 01-11-2010 02:17 PM
It's all in the quotes:
Code:
[mherring@mystical tst]$ ls
xxa  xxb  xxc  xxd
[mherring@mystical tst]$ for fil in *;do echo "test";echo $fil;done
test
xxa
test
xxb
test
xxc
test
xxd
[mherring@mystical tst]$ for fil in "*";do echo "test";echo $fil;done
test
xxa xxb xxc xxd
[mherring@mystical tst]$

rhlee 01-12-2010 03:59 AM
Quote:
Originally Posted by pixellany (Post 3822854)
It's all in the quotes
Yes it is, thank you.

It works now.


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