syntax to use 10 9 8 7 6 5 4 3 2 1 blastoff?

learngeek · 12-03-2012, 03:53 PM

#!/bin/bash
n=1
while [ $n -le 10 ];
do
echo $n
let n++
done

I was not able to get it to reverse with a blastoff

How do I code it?

markush · 12-03-2012, 05:19 PM

Hello learngeek, welcome to LQ,

Code:

#!/bin/bash
n=10
while [ $n -ge 1 ];
do 
        echo $n
        let n--
done

Markus

colucix · 12-04-2012, 03:01 AM

Or simply

Code:

#!/bin/bash
for n in {10..1}
do
  echo $n
done

grail · 12-04-2012, 11:20 AM

Or simpler still:

Code:

printf "%d\n" {10..1}

learngeek · 12-05-2012, 12:42 PM

Thank you markush. I tried the first one. It was easier for me.

One more question I need help with.

How do I write bash to set up the following like this

1 3 2 4 3 5 4 6...100.

I need to write that looks like

1234
3456 and so on.

Thank you

grail · 12-05-2012, 01:05 PM

My I suggest looking into an 'if' statement that checks what number you are up to and simply place a newline after the appropriate entry.