[python] syntax Error : invalid syntax

Python_user · 09-06-2009, 05:48 AM

Hey Guys, I just started with Python scripting.
Please find below the small snippet of if block, When I am trying to go for else if condition ,python shell giving me an error called invalid syntax.

>>>
>>> a, b = 0, 1
>>> if a == 0:
a = 1
print 'Reassigned a to 1'
elif b == 1:

SyntaxError: invalid syntax
>>>

quanta · 09-06-2009, 08:03 AM

Quote:

Originally Posted by Python_user

Hey Guys, I just started with Python scripting.
Please find below the small snippet of if block, When I am trying to go for else if condition ,python shell giving me an error called invalid syntax.

>>>
>>> a, b = 0, 1
>>> if a == 0:
a = 1
print 'Reassigned a to 1'
elif b == 1:

SyntaxError: invalid syntax
>>>

What is the key (or keys combination) did you use after the elif b == 1: command?

Dan04 · 09-06-2009, 12:52 PM

Quote:

Originally Posted by Python_user

Hey Guys, I just started with Python scripting.
Please find below the small snippet of if block, When I am trying to go for else if condition ,python shell giving me an error called invalid syntax.

Code:

>>> a, b = 0, 1
>>> if a == 0:
	a = 1
	print 'Reassigned a to 1'
	elif b == 1:
		
SyntaxError: invalid syntax

Please use CODE tags to post code. Showing the indentation is very important in Python.

The elif needs to be indented the same as the if.