How to turn off the system automatically ?

gardenair · 03-14-2011, 01:10 AM

Hi,
I am using Cent Os 5. I want that the system should shutdown automatically at 7:00 pm daily and next day I manually turn on the system.I have google it but the syntax is not clear.

I use # crontab -e
and write the command
0 19 * * * /sbin/shutdown -h now

I does't apply the command but please guide me that what is * * * after 19
Kindly guide me how can I enable this feature?
thanks in advance,
garden

vishnu_sreekumar · 03-14-2011, 01:30 AM

Scheduling a "shutdown -h now" via a cron job (for root user) that runs at 7.00 PM daily would do that.

Edit the crontab and add the following line
# crontab -e

Code:

  0 19 * * * /sbin/shutdown -h now

Check the man page for crontab (5) for more details.

gardenair · 03-14-2011, 01:36 AM

thanks "vishnu_sreekumar" for the reply. Well what does * * * means ?
If I want to do it at 7:15 PM then how will it write ?
thanks for guiding me
garden

yooy · 03-14-2011, 02:30 AM

Quote:

If I want to do it at 7:15 PM then how will it write ?

15 19 * * * /sbin/shutdown -h now

repo · 03-14-2011, 02:42 AM

I would suggest to take a look at
http://en.wikipedia.org/wiki/Cron

Kind regards

vishnu_sreekumar · 03-21-2011, 01:07 AM

Quote:

Originally Posted by gardenair

thanks "vishnu_sreekumar" for the reply. Well what does * * * means ?
If I want to do it at 7:15 PM then how will it write ?
thanks for guiding me
garden

Assume that you went through the wiki page and found the answer