How to extract the last digit from an input parameter???
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How to extract the last digit from an input parameter???
Hi, I'm looking to find out how do I write a bash script that will take the last digit from a command and display it? Basically I have my script and I want it to take the last number from the date,extract it and place it on a separate line on its own.
yes, it s difficult to figure out how many chars are in the string and then, getting the last.
It is more easy to get the first one, isn't ? well, reverse it first, so the last becomes the first.
Guess what is the name of a command that reverse a string ?
It can be done entirely in the shell (that is without using external commands such as cut and tr) by using Shell Parameter Expansion in conjunction with Arithmetic Expansion. That's not easy so a hint is that it uses ${parameter:offset}
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