Commandline Help Please

K3rm1tTh3Fr0g · 02-02-2017, 01:21 AM

Hello,
Just a heads up I'm using CentOS. So I need to find the number of files and directories in another directory and I need that to be outputted in this format "The number of files and directories in /etc on Thu Oct 16 17:18:16 PDT 2014 is 6162". So far I used the command find /etc -type f | wc -l | awk '{ print strftime(), $0; fflush() }' >output.txt but it just gives me the date and number of files and directories. I need to get it worded correctly. Please help.

pan64 · 02-02-2017, 01:35 AM

I would suggest you to use something like this:

Code:

awk '{ printf("The number of files and directories in %s on %s", $0, strftime()) } '
(not tested)

see how printf works https://www.gnu.org/software/gawk/ma...-Examples.html http://www.math.utah.edu/docs/info/gawk_7.html.
fflush is not required.

Turbocapitalist · 02-02-2017, 01:53 AM

With the line as given, the correct wording for the printf function should leave out naming directories because they are not included in the search:

Code:

"The number of files in %s on %s \n"

If the number of directories is to be included, the search should include them with a logical or:

Code:

find /etc/ \( -type f -o -type d \) -print

aragorn2101 · 02-02-2017, 04:00 AM

Hi,

this can be easily done with standard shell syntax, no need for awk. Give this a try:

Code:

echo "The number of files in /etc on $(date +"%a %b %d %T %Z %Y") is $(find /etc -type f 2>/dev/null | wc -l)."