CLI

smileybri · 04-16-2015, 12:42 PM

So I extract an update to a package that creates one of the folders below and then I run "$(find . -name install.sh)" to find and install the update. It seems to go just fine. How? If the other versions were also there? Which install.sh gets run?

# find -name install.sh
./Program_5.1.8341.5506_Install/install.sh
./Program_5.0.8132.5459_Install/install.sh
./Program_5.2.8724.5567_Install/install.sh
./Program_5.1.8473.5522_Install/install.sh

John VV · 04-16-2015, 12:50 PM

whatever one YOU select

veerain · 04-16-2015, 12:51 PM

See install script which unpacks and runs.

suicidaleggroll · 04-16-2015, 02:24 PM

Quote:

Originally Posted by smileybri

I run "$(find . -name install.sh)" to find and install the update.

find does not install anything. It does exactly what its name implies, it just finds all files that match the parameters you gave it (-name install.sh) and prints them out.

Quote:

Originally Posted by smileybri

Which install.sh gets run?

None of them.

edit: Actually I see you ran "$(find . -name install.sh)" rather than "find . -name install.sh". In that case it will likely run the first one it finds. You're much better off separating the find and the execution:

Code:

find . -name install.sh

Pick the one you want, and then run it

Code:

./Program_5.2.8724.5567_Install/install.sh

rknichols · 04-16-2015, 03:27 PM

Quote:

Originally Posted by suicidaleggroll

Actually I see you ran "$(find . -name install.sh)" rather than "find . -name install.sh". In that case it will likely run the first one it finds.

It will run the first one it finds, passing all the rest as arguments. Depending on what that script does with its arguments, the result might be "interesting".