bash command that lists all members of a group by their real names

quadmore · 11-07-2005, 09:36 AM

Hello!

I'm writing a manual for Linux newbies and I am looking for a command that would list all members of a group by their real names (our network logins are pretty cryptic and useless).

Doing the command:
cat /etc/group | sort

is too much info and gives out the cryptic logins.

For example, in /etc/passwd I am listed as:
bszogh:x:1017:502:Bertrand Szoghy:/home/d00bsz:/bin/bash

I want a command such as:

showmembers <groupname>

which would display:

Bertrand Szoghy
Jane Doe
John Doe

Thanks!
Bert

fatra2 · 11-07-2005, 09:39 AM

Just go into a bash shell and type twice the Tab button. You will have a list of all the commands.

pritchardtom · 11-07-2005, 09:40 AM

If you man the users command, I am pretty sure that there is an option that prints out the names of the users, and not their IDs.

I would check for you but at the moment I am stuck in my Windows sysyem in the Uni Library.

quadmore · 11-07-2005, 09:42 AM

Display all 1722 possibilities? (y or n)

Not useful, that's why I posted here after googling the group commands.

Bert

tredegar · 11-07-2005, 10:46 AM

OK, you need a hint or two?
man cat
man cut
man grep
man sort
man sed (but the above should be enough!)

Oh, and don't forget the | ("pipe") operator (see man bash)

Have fun