date in awk

raj_deep2k1 · 01-21-2006, 06:57 AM

hello i am facing problem in the following shell script.please help me.
file is as below

#Rwatch.sh
clear
tail -F /var/log/squid/access.log | awk '{print $3 "\t" date $7}' >> output.txt

acid_kewpie · 01-21-2006, 07:09 AM

so what problem are you having?

raj_deep2k1 · 01-21-2006, 07:15 AM

Quote:

Originally Posted by acid_kewpie

so what problem are you having?

in the output.txt the date is not displaying.......

-Rajendra

acid_kewpie · 01-21-2006, 07:18 AM

sample input text would be handy... can't test something without input, and i don't think too many people will have squid logs of their own...

bulliver · 01-21-2006, 07:31 AM

Code:

tail -F /var/log/squid/access.log | awk '{print $3 "\t" "date " $7}' >> output.txt

...will work if you are trying to print 'date' literally.

If you want 'the date' then try:

Code:

tail -F /var/log/squid/access.log | awk '{print $3 "\t" strftime() " " $7}' >> output.txt

raj_deep2k1 · 01-21-2006, 08:09 AM

Quote:

Originally Posted by bulliver

Code:

tail -F /var/log/squid/access.log | awk '{print $3 "\t" "date " $7}' >> output.txt

...will work if you are trying to print 'date' literally.

If you want 'the date' then try:

Code:

tail -F /var/log/squid/access.log | awk '{print $3 "\t" strftime() " " $7}' >> output.txt

thanks a lot

-Rajendra