awk problem

jpostma · 10-22-2003, 04:21 AM

I want to create a new list of ls -l. This new list includes the filename or directoryname. I added in awk Print $9. The problem is if the filname or directoryname contains a space only the first part of the filename will be printed in the new list. E.g. if the directory is "New Folder" only New will be printed.

How can I solve this problem?

Johannes

SaTaN · 10-22-2003, 04:46 AM

Code:

 
ls -l | awk '{for(i=9;i<=NF;i++){printf $i" "}{print ""}}'

This would output all the fields starting from the 9th field.
NF contains the number of fields of the line for which awk is done.

AMMullan · 10-22-2003, 04:49 AM

Hmmm to make it easier you could just use

ls -l | awk '{print $8 $9}'

AMMullan · 10-22-2003, 04:52 AM

Oops i meant $9 and $10

basically, every word between whitespace is a higher number - i.e.

Hello World From LQ

$1 $2 $3 $4

hope this helps

jkobrien · 10-22-2003, 05:20 AM

Couldn't you use substr?

ls -l | awk '{print substr($0,57)}'

works for me, but if the file is a link, you get all that stuff too.

John

jpostma · 10-22-2003, 05:52 AM

Thanks for the answers. I will try it tonight. Maybe the problem still exits if the directoryname contains more than one space. E.g.

New Folder (two spaces between New and Folder)

Johannes

jkobrien · 10-22-2003, 06:04 AM

No, usually awk will treat consecutive whitespace as one.

But the simplest answer is probably...

ls -1 // That switch is "one", not "ell".

John

AMMullan · 10-22-2003, 06:07 AM

LOL Didn't even think of that