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I have installed Red Hat 7.1 on a machine and begun attempting to create a firewall using iptables. I believe I know what I need to do to make it happen but I began to write a script file which does not work as I expect it to. I shortened the file up to try to figure out what's happening. This is my script named rc.firewall
#!/bin/sh
iptables -P INPUT DROP
iptables -P OUTPUT DROP
iptables -P FORWARD DROP
exit 0
iptables is the program name, -P means change the default policy of the chain, INPUT is the chain, and DROP is the policy I want.
If I type the lines for iptables from the prompt the policy changes as expected.
When I attempt to run my script by typing sh rc.firewall, from the appropriate directory, I get the following,
iptables: Bad policy name
iptables: Bad policy name
iptables: Bad policy name
'c.firewall: exit: bad non-numeric arg `0
It appears to me that iptables is run from the script, it recognizes the -P to change the policy, I believe it recognizes the chain name but drops the ball on the policy. Yes it is case sensitive and I am using the correct case. I have tried both. Further it does not seem to recognize 0 (zero) as a valid arguement after exit. However, typing sh to enter the shell then exit 0 doesn't generate an error message. Just for more info from the shell I typed exit n , a letter instead of a number and got the error message. Also I edited the script and put a semi-colon after the zero and that error message went away. Okay, what have I done wrong? Thanks in advance to whoever knows whats going on.
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No definate answer, just an idea...
