Does the line:
Code:
if (c == ' ' || c == '\n' || c = '\t')
right?
Here is the source code I copy from <<the c programming language>>
Code:
#include <stdio.h>
#define IN 1 /* inside a word */
#define OUT 0 /* outside a word */
/* count lines, words, and characters in input */
main()
{
int c, nl, nw, nc, state;
state = OUT;
nl = nw = nc = 0;
while ((c = getchar()) != EOF) {
++nc;
if (c == '\n')
++nl;
if (c == ' ' || c == '\n' || c = '\t')
state = OUT;
else if (state == OUT) {
state = IN;
++nw;
}
}
printf("%d %d %d\n", nl, nw, nc);
}
however, when I compile it, the compiler said:
"[root@localhost second]# gcc c.c -o c
c.c: In function `main':
c.c:17: invalid lvalue in assignment"
What is wrong with the program?
Thank you.