about the command /usr/bin/install

pan64 · 08-07-2014, 03:39 AM

I have tried the following:

Code:

~$ install -m 666 -d /tmp/aaa/bbb/ccc
~$ ls -lda /tmp/aaa
drwxr-xr-x 3 user group 60 Aug  7 10:24 /tmp/aaa
~$ ls -lda /tmp/aaa/bbb
drwxr-xr-x 3 user group 60 Aug  7 10:24 /tmp/aaa/bbb
~$ ls -lda /tmp/aaa/bbb/ccc
drw-rw-rw- 2 user group 40 Aug  7 10:24 /tmp/aaa/bbb/ccc

we can see aaa and bbb were created using umask and only ccc was created using the flags given (-m 666).

Is there any way to set the given permissions of all the dirs - not only the last one, but all the parents (of course I can write a script to do that). Is there any way to introduce a new flag (something like -r as recursive, -f force to set)? Does it make any sense?

bigrigdriver · 08-07-2014, 12:09 PM

When you give the destination directory as part of a /path/to/directory, the last directory in the path is the destination, not each directory in the path.

In order to have each directory in the path also receives the desired permissions, try this:

Code:

install -m 666 -d /tmp/aaa -d /tmp/aaa/bbb -d /tmp/aaa/bbb/ccc

pan64 · 08-08-2014, 12:10 AM

yes, that's what I would like to simplify. Actually I have an environment variable, and use something like install -m 755 -d $DIR/even/more/subdirs several times. Would be nice to have a switch (or two?) instead of evaluating that arbitrary expression in a script.