[SOLVED] using cut

puth · 03-11-2010, 09:57 AM

hello,

i have some thing like the below in a file.

linux example1
linux example10
linux example32
read error
linux example2

i need to pick all the words that are just after linux and place them in another file.I tried to use cut -d '' -f2 but at some places where the line is the not started with linux i get the output as below

example1
example10
example32
error
example2

i want the output as
example1
example10
example32
example2.

how to modify my cut statement?

H_TeXMeX_H · 03-11-2010, 10:07 AM

I think you should use awk, that way you can test if the first word is 'linux', and if it is, then you print the second word.

See:
http://www.grymoire.com/Unix/Awk.html

rn_ · 03-11-2010, 10:11 AM

grep, sed , awk , perl , shell -- too many choices.....

since you already have the 'cut' part down, you could simply add a grep before it.

puth · 03-11-2010, 01:30 PM

i used grep "linux"|awk '{print $2}' and got the desired output.

H_TeXMeX_H · 03-11-2010, 02:55 PM

But, that isn't quite the solution, because linux could be second or third and it would still grep that line.

Maybe

Code:

awk '{ if ($1 == "linux") print $2 }' input.txt