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Old 09-16-2009, 05:13 PM   #1
ncsuapex
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Registered: Dec 2004
Location: Raleigh, NC
Distribution: CentOS 2.6.18-53.1.4.el5
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help with cut command using find. Cut last 8 characters leaving the rest


Im trying to use find and cut, but instead of cutting the characters I want to save, I want to cut those characters leaving the rest of the results of my find command.


For example:

I have a file with the same name in multiple directories. I want to find just the directories that file is in but I do not want to print the file name.

/path/to/file.txt
/path/to/another/file.txt
/path/to/yet/another/file.txt

So my "command" would be:
[QUOTE]find / -name file.txt print just the directories[/QUOTE

Ive tried the type d flag but it doesnt seem to work if you are using file names)

So my results would be
/path/to/
/path/to/another/
/path/to/yet/another/


Ive tried various pipes to cut to remove the last 8 characters as that's my only constant. But instead of cutting file.txt off and leaving the directories it only cuts file.txt so my result is:
file.txt



Or is there a way to use find to find a file name but just print the directories they are in?



commands Ive tried:

Quote:
find / -name file | cut -c -8
This cuts everything after the first 9 characters of my find result. I want to cut the last 8 characters of the result leaving the rest of the line.



Confused yet?

Thanks!
 
Old 09-16-2009, 05:41 PM   #2
catkin
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Registered: Dec 2008
Location: Tamil Nadu, India
Distribution: Servers: Debian Squeeze and Wheezy. Desktop: Slackware64 14.0. Netbook: Slackware 13.37
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Code:
find / -type f -name file.txt -print0 | while IFS= read -r -d '' filename
do
    echo "${filename#/*}"
done
 
Old 09-16-2009, 05:44 PM   #3
centosboy
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Registered: May 2009
Location: london
Distribution: centos5
Posts: 1,137

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[QUOTE=ncsuapex;3685865]Im trying to use find and cut, but instead of cutting the characters I want to save, I want to cut those characters leaving the rest of the results of my find command.


For example:

I have a file with the same name in multiple directories. I want to find just the directories that file is in but I do not want to print the file name.

/path/to/file.txt
/path/to/another/file.txt
/path/to/yet/another/file.txt

So my "command" would be:
Quote:
find / -name file.txt print just the directories[/QUOTE

Ive tried the type d flag but it doesnt seem to work if you are using file names)

So my results would be
/path/to/
/path/to/another/
/path/to/yet/another/


Ive tried various pipes to cut to remove the last 8 characters as that's my only constant. But instead of cutting file.txt off and leaving the directories it only cuts file.txt so my result is:
file.txt



Or is there a way to use find to find a file name but just print the directories they are in?



commands Ive tried:



This cuts everything after the first 9 characters of my find result. I want to cut the last 8 characters of the result leaving the rest of the line.



Confused yet?

Thanks!
one way..

pipe to
Code:
sed -e's/........$//g'

or even

Code:
perl -pi -e 's/.{8}$//'

Last edited by centosboy; 09-16-2009 at 05:47 PM.
 
Old 09-16-2009, 05:47 PM   #4
ncsuapex
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Registered: Dec 2004
Location: Raleigh, NC
Distribution: CentOS 2.6.18-53.1.4.el5
Posts: 770

Original Poster
Rep: Reputation: 43
Thanks for the response. After I posted I figured it out. I was putting my - in the wrong place. It should be after your number to indicate you want to cut from left to right


Quote:
find / -name file.txt | rev | cut -c 8- | rev
 
Old 09-16-2009, 09:55 PM   #5
linuxraja
LQ Newbie
 
Registered: Sep 2009
Posts: 17

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Quote:
Originally Posted by ncsuapex View Post
Thanks for the response. After I posted I figured it out. I was putting my - in the wrong place. It should be after your number to indicate you want to cut from left to right

Thats one thingy funny about shell script ... syntax and even spaces matter!


testing = 123

and

testing=123

have completely different meanings !!!

// removed spam link

Last edited by crabboy; 11-01-2010 at 09:03 AM.
 
  


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