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Old 09-14-2001, 02:45 AM   #1
elconde
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Registered: Sep 2001
Location: Cherry Hill, NJ
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Angry Simple C Shell script is not so simple


Imagine the following program in C Shell. What should I put in place of the question marks to assign the variables a, b, c, d or any other variables like them that may show up to the last number after the last backslash.


set a = "a/b/c/d/1/2/3"
set b = "e/r/r/4"
set c = "dew/gr/34/op3/22"
set d = "33/22/11/1?"
.
.
.

??????????????????????


So, I want to set the variables a, b, c, d to 3, 4, 22, and 1?. I tried using awk, but it was a disaster.

HELP!!!
 
Old 09-16-2001, 10:20 PM   #2
crabboy
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I would use bourne shell, C shell stinks when writing scripts. Use awk to find the number of slashes in the line, then use cut to cut out the last field. You will need to set the field seperator for awk. I tried it quickly here and awk didn't like the '/' as a delimiter. You can probably hack at it a bit to make it work.
Code:
FIELDS=`echo $A | awk ' { FS = "/"; print NF } '`
LAST=`echo $A | cut -d'/' -f$FIELDS`
This does not work, but I hope it will get you started.
 
Old 09-16-2001, 11:53 PM   #3
elconde
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thanks

Thanks for the advice. I'll try it out.


-Robert
 
  


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