Simple Shell Script Help

Kristijan · 06-13-2005, 07:06 PM

Hi,

First time shell scripting, so I'm just trying to get by with man pages and the sticky in this forum.

This is the output of the following command:

Code:

VIC_DAS36 (root): /home/tsioper/status 2>/dev/null | grep CAL-SERVER2 | awk '{ print $5 }'
Serving

and this is the script I'm trying to create:

Code:

CAL-2=`/home/tsioper/status 2>/dev/null | grep CAL-SERVER2 | awk '{ print $5 }'` 
CAL-4=`/home/tsioper/status 2>/dev/null | grep CAL-SERVER4 | awk '{ print $5 }'`  
if [ '$CAL-2' = 'Stopped' ]
         then
                 echo CAL Server 2 has gone down and/or stopped serving! | mail -s "WARNING: CAL Server" fake@email.com
elif
if [ '$CAL-4' = 'Stopped' ]
         then
                 echo CAL Server 4 has gone down and/or stopped serving! | mail -s "WARNING: CAL Server" fake@email.com 
fi

Now what I want the script to do is e-mail me when the output of the command is 'Stopped'.

This is what I get when I try running it:

Code:

VIC_DAS36 (root): ./CAL-test ./CAL-test[7]: CAL-2=Serving:  not found. 
./CAL-test[8]: CAL-4=Serving:  not found. 
./CAL-test[10]: 0403-057 Syntax error at line 13 : `if' is not matched.

Any input is accreciated

-Kristijan

Kristijan · 06-13-2005, 07:13 PM

I've made a slight change to the script to use 2 if condition statements, then the single one.

It now reads like this:

Code:

CAL-2=`/home/tsioper/status 2>/dev/null | grep CAL-SERVER2 | awk '{ print $5 }'`
CAL-4=`/home/tsioper/status 2>/dev/null | grep CAL-SERVER4 | awk '{ print $5 }'`

if [ $CAL-2 = 'Stopped' ];
        then
                echo CAL Server 2 has gone down and/or stopped serving! | mail -s "WARNING: CAL Server" fake@email.com
fi
if [ $CAL-4 = 'Stopped' ];
        then
                echo CAL Server 4 has gone down and/or stopped serving! | mail -s "WARNING: CAL Server" fake@email.com
fi

When I run it, I now get the following error:

Code:

VIC_DAS36 (root): ./CAL-test
./CAL-test[7]: CAL-2=Serving:  not found.
./CAL-test[8]: CAL-4=Serving:  not found.

-Kristijan

Dark_Helmet · 06-13-2005, 08:52 PM

I don't believe you can have a '-' in a variable name.

Try CAL_2 and CAL_4.

Kristijan · 06-13-2005, 09:13 PM

Dark_Helmet,

The name of the variable seemed to be the problem. It seems that I can't have a - in the variable name. I have replaced it with an _ and it all works fine now.

Thanks for your help.

Cheers,
-Kristijan