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Old 09-04-2008, 10:21 AM   #1
eantoranz
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Question python-ldap: How to catch an error on binding?


I'm just giving my first baby steps on python-ldap.

I have on purpose set up a connection that has to fail on binding... but I don't get to catch an error:

Code:
import ldap
import sys
ldapURI = "ldap://" + ldapServer + ":" + str(ldapPort)
print "LDAP URI: " + ldapURI
ldapConn = ldap.initialize(ldapURI)
try:
    ldapConn.bind(ldapLoginID, ldapLoginPasswd, ldap.AUTH_SIMPLE)
except:
    print "Caught an error!", sys.exc_info()
    sys.exit(-1)
When I run it, this is the output:
Code:
LDAP URI: ldap://10.0.1.251:389
And this is the network trace:
Code:
1	0.000000	10.0.1.31	10.0.1.251	TCP	55961 > ldap [SYN] Seq=0 Win=5840 Len=0 MSS=1460 TSV=22309611 TSER=0 WS=6
2	0.000318	10.0.1.251	10.0.1.31	TCP	ldap > 55961 [SYN, ACK] Seq=0 Ack=1 Win=5792 Len=0 MSS=1460 TSV=16565465 TSER=22309611 WS=5
3	0.000357	10.0.1.31	10.0.1.251	TCP	55961 > ldap [ACK] Seq=1 Ack=1 Win=5888 Len=0 TSV=22309612 TSER=16565465
4	0.000434	10.0.1.31	10.0.1.251	LDAP	bindRequest(1) "cn=root,dc=fake,dc=domain,dc=com" simple 
5	0.000642	10.0.1.251	10.0.1.31	TCP	ldap > 55961 [ACK] Seq=1 Ack=49 Win=5792 Len=0 TSV=16565465 TSER=22309612
6	0.002085	10.0.1.251	10.0.1.31	LDAP	bindResponse(1) invalidCredentials 
7	0.002144	10.0.1.31	10.0.1.251	TCP	55961 > ldap [ACK] Seq=49 Ack=15 Win=5888 Len=0 TSV=22309612 TSER=16565465
8	0.004096	10.0.1.31	10.0.1.251	LDAP	unbindRequest(2) 
9	0.004144	10.0.1.31	10.0.1.251	TCP	55961 > ldap [FIN, ACK] Seq=56 Ack=15 Win=5888 Len=0 TSV=22309612 TSER=16565465
10	0.004172	10.0.1.31	10.0.1.251	TCP	55961 > ldap [RST, ACK] Seq=57 Ack=15 Win=5888 Len=0 TSV=22309612 TSER=16565465
How can I catch that problem in the code?
 
  


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