I'm just learning PHP and trying to figure out how to accept URL arguments (if that's even the right term). So, if this is the URL (to the file on my web server)

http://mysite.com/my_page.php?type=1&page=2

How would I rertreive the arguments after the question mark? I plan on passing the arguments to a MySQL database to generate dymanic pages.

I've googled this for hours with no luck.

This is really more of a PHP question than a linux question, however...

Variables in PHP depend on the way in which it was submitted (GET, POST or PUT). If you are passing some variables via your URL, it is a GET request.

In recent versions of PHP, these values are available in the global $_GET array variable. In older versions (pre-3.x), you use $HTTP_GET_VARS.

For example, using the following URL:
http://mysite.com/my_page.php?type=1&page=2

You would get to your variables 'type' and 'page' this way:

$_GET["type"] and $_GET["page"]

If it was submitted via a POST request, you'd get to your variables like this:
$_POST["type"] and $_POST["page"]

Using your URL, $_GET["type"] would equal '1' and $_GET["page"] would equal '2'.

Check this page for more info:
http://us2.php.net/reserved.variables

Also, you may want to check PHP Builder (www.phpbuilder.com/board/), as it is specific to PHP related questions.

Hope that helps.

Thanks for the advice. Works perfectly



And, for the record:
"This forum is for all programming questions.
The question does not have to be directly related to Linux and any language is fair game."