multiple variable from differnet file

jayesha18 · 12-22-2006, 01:01 AM

Dear all,
I trying to write the shell script , which will take variables from a 3 different files , and display all at once on one line.
Example :--
======
I have following 3 files , which contain data in following order
1) /tmp/name
2) /tmp/age
3) /tmp/country
[root@jayesh ~]# cat /tmp/name
"sachin"
"lara"
"rahul"
[root@jayesh ~]# cat /tmp/age
"35"
"38"
"32"
[root@jayesh ~]# cat /tmp/country
"India"
"Westindies"
"India"

Now I want the output as follows after running the shell script :--

"sachin","India","35"
"lara","Westindies","38"
"raul","India","32"

That means i want to put variable from this 3 file and want to just echo on screen.At present i am only able to get variable from one file only by "for i in " loop
How do i get the above output ? which loop and which command should i use in this case ? plz help and guide me

Thanks & Regards
Jayesh

unSpawn · 12-22-2006, 06:10 AM

I hope this isn't homework.

Easiest way is to use arrays:

Code:

#!/bin/sh -
array0=(`cat  /tmp/name`); array1=(`cat  /tmp/age`); array2=(`cat  /tmp/country`)
for i in `seq 0 $[${#array0[@]}-1]`; do
 echo "${array0[$i]},${array1[$i]},${array2[$i]}"
done
exit 0

Note that 0) this will only work if the position of the data in all files is synced, 1) if you have space separated values in any of the files you must fiddle with the IFS and 2) I assert you are capable of adding the double quotes back in yourself.

Code:

function help() { echo "Bash scripting guides:
http://www.tldp.org/HOWTO/Bash-Prog-Intro-HOWTO.html 
http://www.tldp.org/LDP/Bash-Beginners-Guide/html/index.html 
http://www.tldp.org/LDP/abs/html/"; }

Nota bene: do yourself a favour and do not script as root account user.

demon_vox · 12-22-2006, 10:14 AM

The really easiest way (just kidding unSpawn

) is to use the paste command (check the man!).

To acomplish what you want just write:

Code:

paste -d , name country age

And off you go

Cheers!