[SOLVED] for loop in bash

ip_address · 05-17-2012, 10:23 AM

Hello everyone,

As we can use this bash script

Code:

#!/bin/bash

for counter in {1..3};do

echo "$counter"

done

to generate this output:

Code:

1
2
3

How can I loop around in bash from 1 to 100 and A to Z all together.

so that output could be

Code:

1
2
3
4
.
.
.
.
100
A
B
C
.
.
.
Z

Thanks ..

millgates · 05-17-2012, 10:28 AM

Hi, how about

Code:

#!/bin/bash

for counter in {1..100} {A..Z};do

echo "$counter"

done

or, even better:

Code:

printf "%s\n" {1..100} {A..Z}

ip_address · 05-17-2012, 11:02 AM

@millgates .. thank you very much!!! That worked.

David the H. · 05-18-2012, 08:41 AM

See here for all you ever wanted to know about brace expansion:

http://wiki.bash-hackers.org/syntax/expansion/brace

And this link covers printf:

http://wiki.bash-hackers.org/commands/builtin/printf