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ip_address 05-17-2012 10:23 AM
for loop in bash
 
Hello everyone,

As we can use this bash script

Code:
#!/bin/bash

for counter in {1..3};do

echo "$counter"

done


to generate this output:

Code:
1
2
3

How can I loop around in bash from 1 to 100 and A to Z all together.

so that output could be

Code:
1
2
3
4
.
.
.
.
100
A
B
C
.
.
.
Z
Thanks ..

millgates 05-17-2012 10:28 AM
Hi, how about

Code:
#!/bin/bash

for counter in {1..100} {A..Z};do

echo "$counter"

done
or, even better:

Code:
printf "%s\n" {1..100} {A..Z}

ip_address 05-17-2012 11:02 AM
@millgates .. thank you very much!!! That worked.

David the H. 05-18-2012 08:41 AM
See here for all you ever wanted to know about brace expansion:

http://wiki.bash-hackers.org/syntax/expansion/brace


And this link covers printf:

http://wiki.bash-hackers.org/commands/builtin/printf


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