[SOLVED] extract just the package name without version number from .txt file

socalheel · 11-06-2014, 07:22 PM

i have a file with about 900 lines of packages that are installed on my server. i need to strip all the version information off, and give me only the package name.

here is a snipit

Code:

wbt-virtual-server-theme-8.8-1.noarch
webalizer-2.21_02-3.3.el6.x86_64
webmin-1.680-1.noarch
wget-1.12-1.11.el6_5.x86_64
which-2.19-6.el6.x86_64
wireless-tools-29-5.1.1.el6.x86_64
words-3.0-17.el6.noarch
xdg-utils-1.0.2-17.20091016cvs.el6.noarch
xml-common-0.6.3-32.el6.noarch
xmlrpc-c-1.16.24-1210.1840.el6.x86_64
xmlrpc-c-client-1.16.24-1210.1840.el6.x86_64
xorg-x11-drv-ati-firmware-7.1.0-3.el6.noarch
xorg-x11-font-utils-7.2-11.el6.x86_64
xz-4.999.9-0.3.beta.20091007git.el6.x86_64
xz-libs-4.999.9-0.3.beta.20091007git.el6.x86_64
xz-lzma-compat-4.999.9-0.3.beta.20091007git.el6.x86_64
yp-tools-2.9-12.el6.x86_64
ypbind-1.20.4-30.el6.x86_64
yum-3.2.29-43.el6_5.noarch
yum-metadata-parser-1.1.2-16.el6.x86_64
yum-plugin-security-1.1.30-17.el6_5.noarch
yum-rhn-plugin-0.9.1-49.el6.noarch
yum-utils-1.1.30-17.el6_5.noarch
zd1211-firmware-1.4-4.el6.noarch
zip-3.0-1.el6.x86_64

i need only this:

Code:

wbt-virtual-server-theme
webalizer
webmin
wget
which
wireless-tools
words
xdg-utils
xml-common
xmlrpc-c-
xmlrpc-c-client
xorg-x11-drv-ati-firmware
xorg-x11-font-utils
xz
xz-libs
xz-lzma-compat
yp-tools
ypbind
yum
yum-metadata-parser
yum-plugin-security
yum-rhn-plugin
yum-utils
zd1211-firmware
zip

how can i do that?

socalheel · 11-06-2014, 07:30 PM

i mean, i can accomplish this inside vim with multiple " :%s/ //g" commands ... but how could i do this from the command line?

metaschima · 11-06-2014, 08:08 PM

This is what I use for a package management script I wrote, it seems to work here too, but do some more tests

Code:

cat test | rev | cut -d- -f 1-2 --complement | rev

evo2 · 11-06-2014, 08:22 PM

Hi,

looks to me you want to delete everything after the first hyphen that is followed by a number. So:

Code:

sed 's/-[0-9].*//g'

HTH,

Evo2.

syg00 · 11-06-2014, 08:31 PM

Normally I'd say just create some regex equivalent to the vim commands and use sed, but regex being greedy messes that. How about plain old bash parameter substitution ?

Code:

while read line ; do echo ${line%%-[0-9]*} ; done < infile.txt

(presumes you want to lose everything that is after the first -[:digit:])

socalheel · 11-06-2014, 08:43 PM

Quote:

Originally Posted by evo2

Hi,

looks to me you want to delete everything after the first hyphen that is followed by a number. So:

Code:

sed 's/-[0-9].*//g'

HTH,

Evo2.

oh man that is so freakin simple ... i think when i first saw all the variations and multiple fields followed by a hyphen i got overwhelmed for a second.

exactly what i needed.

thanks dude.