" cut command "

sharath.bv · 02-04-2008, 01:10 AM

Hi all,

I want display only the fist word from each lines of the file.
In each line the words are seperated by TAB's.
----------------------------------
cut -d : -f 1 filename
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angrybanana · 02-04-2008, 01:17 AM

Code:

cut -f 1 filename

-d sets the delimiter, in your case you're setting it to ':', it defaults to tab
`man cut` for more info

colucix · 02-04-2008, 01:19 AM

Code:

cut -f1 filename

TAB is the default delimiter.

Edit: ooops... too late!

sharath.bv · 02-04-2008, 01:32 AM

Thanks this command "cut -f 1 filename" works.

But this above command is not working for the below file contents...
----------------------------------------------------
first.xls.ods 1.1 Mon Dec 19 10:52:30 2005 b
test.doc 1.1 Tue Jun 5 10:51:34 2007 b
SourceCode (directory)
TCD (directory)
TM (directory)
design (directory)
prasanth (directory)
tech_docs (directory)
test scripts (directory)

----------------------------------------------------------
Here also i want to display only the first field of each line...

colucix · 02-04-2008, 01:49 AM

I guess it still depends from the delimiter. If space-delimited this should work

Code:

cut -d\  -f1 filename

please note the double space after backslash: the first is an escaped blank space "\ ". In alternative you can use awk which recognizes either TAB or SPACE as "field separator" so you don't need to specify it every time:

Code:

gawk '{print $1}' filename

sharath.bv · 02-04-2008, 02:38 AM

Thanks all i got the answer......