case

sharathkv · 07-27-2006, 10:49 PM

Hi,

In my script, I want to exit if the input is
not Y or y. I am using case:

Code:

case $res in
~[Yy])
     echo user chose to canel operation
     exit 1
     ;;
esac

How do I negate the above ~[Yy]?

I tried ~[Yy]. The script is not exiting is input is not Y or y.

Thanks
Shar

crazyjimbo · 07-27-2006, 11:04 PM

Instead of ~[yY], use [^yY]. The ^ tells it to match anything EXCEPT that in the bracket.

sharathkv · 07-27-2006, 11:21 PM

This is not working.

Code:

echo "Enter input"
read res
case $res in
[^Yy])
     echo user chose to cancel operation.
     exit 1
     ;;
esac
echo continuing with the operation



$ ./a.ks
Enter input
!
continuing with the operation
$ ./a.ks
Enter input
m
continuing with the operation

crazyjimbo · 07-27-2006, 11:41 PM

I copied and pasted your script exactly and it works on my machine. Which shell are you using?

The other thing I can think of is that the script will only exit on single characters. If you enter any more than one then it will continue regardless. I'm not too hot on scripting but I'll play around and see what I can come up with.

zhangmaike · 07-27-2006, 11:44 PM

If you're running this script in ksh (Korn shell) instead of sh or bash, use [!Yy] instead of [^Yy].

ksh uses a slightly different syntax for patterns.

See man ksh for more information.

sharathkv · 07-28-2006, 07:03 AM

Sorry for the late reply. I was a bit busy.

Yes I am using ksh.Thanks crazyjimbo for trying.

Thanks zhangmaike,it's working now.

Bye
Shar