hi all,

i'm trying to find out how to show files having a particular format. i.e.

files
o570345.out
o5703451.out
XX_570345_1.RTF

so when i search for files using
ls *570345*

it shows all three files but actually i don't like to see the second file o5703451.out because 5703451 is different from 570345. how do i go about this?

thanks

So is "XX_570345_1.RTF" ... can you come up w/ more
specific rules? At the end of the day you'll need to
filter stuff out, either using grep or some funky
bash ways :}


Cheers,
Tink

Assuming the only exception is no number:

1 members found this post helpful.

hi,

thanks for the replies.. basically the rule is the 570345 is actually an id of a particular request. and a request may have more than 1 output like in the example.. output naming conventions will contain the request id (570345 in the example) but will not have a number before or after the request id.. so for the request id 570345, it can have outputs like:

o570345.out
o570345.req
XX_570345_1.RTF

if there is another request id 5703451 then this request can produce outputs like:
o5703451.out
o5703451.req
XX_5703451_1.PDF

but what i want is to search for all outputs given a request id (570345 in the sample) and it should give me the following:
o570345.out
o570345.req
XX_570345_1.RTF

thanks.

this seems to be doing the trick. i'll do some more testing and get back to you.

thanks.