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Old 02-23-2005, 11:18 AM   #1
meadensi
LQ Newbie
 
Registered: Feb 2005
Posts: 18

Rep: Reputation: 0
Bash For Loops gives syntax error


Hello,

I have typed in a bash script for a Firewall book by Robert Ziegler and I am debugging my typos and I am stuck on my latest.

The bash code hits a for loop

Code:
# Disable Source Routed Packets
for f in /proc/sys/net/ipv4/conf/*/accept_source_route; do
    echo 0 > $f
done
which gives a syntax error near unexpected token do'

I checked the line and its as printed. I've checked the directory wildcard and its correct for my distro (Fedora Core 3).

I've tried putting the do on the next line and stripping off the semi-colon but none of this corrects the behaviour.

Any ideas anyone, I'm stuck here until help is forthcoming.

Thanks in advance
Meadensi
 
Old 02-23-2005, 11:21 AM   #2
Matir
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Registered: Nov 2004
Location: San Jose, CA
Distribution: Ubuntu
Posts: 8,507

Rep: Reputation: 118Reputation: 118
The "do" must be on the same line as the first statement. Specifically, it must be part of the first statement.
 
Old 02-23-2005, 11:30 AM   #3
meadensi
LQ Newbie
 
Registered: Feb 2005
Posts: 18

Original Poster
Rep: Reputation: 0
Thankyou very much.

Yes your suggestion fixes the problem and the following code works

Code:
# Disable Source Routed Packets
for f in /proc/sys/net/ipv4/conf/*/accept_source_route
do echo 0 > $f
done
Thanks again for fast response.
Meadensi
 
  


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