Bash For Loops gives syntax error

meadensi · 02-23-2005, 10:18 AM

Hello,

I have typed in a bash script for a Firewall book by Robert Ziegler and I am debugging my typos and I am stuck on my latest.

The bash code hits a for loop

Code:

# Disable Source Routed Packets
for f in /proc/sys/net/ipv4/conf/*/accept_source_route; do
    echo 0 > $f
done

which gives a syntax error near unexpected token do'

I checked the line and its as printed. I've checked the directory wildcard and its correct for my distro (Fedora Core 3).

I've tried putting the do on the next line and stripping off the semi-colon but none of this corrects the behaviour.

Any ideas anyone, I'm stuck here until help is forthcoming.

Thanks in advance
Meadensi

Matir · 02-23-2005, 10:21 AM

The "do" must be on the same line as the first statement. Specifically, it must be part of the first statement.

meadensi · 02-23-2005, 10:30 AM

Thankyou very much.

Yes your suggestion fixes the problem and the following code works

Code:

# Disable Source Routed Packets
for f in /proc/sys/net/ipv4/conf/*/accept_source_route
do echo 0 > $f
done

Thanks again for fast response.
Meadensi