[SOLVED] (Not so) Simple awk question.

bezoar · 09-14-2009, 11:46 AM

df -k | sed 1d | awk '$5>90 {print}'

I have a work around but do NOT understand why the above will not pick up a file system that is 100% full. 90+ it finds. But not 100%.

My work around:
df -k | sed 1d | awk '$5>90 || $5 =="100%" {print}'

Any solution to my dilemma greatly appreciated.

Skiph

David the H. · 09-14-2009, 12:16 PM

I believe the problem is that awk is doing the comparison as a string and not a numeric operator. And in strings "10" is less than "9". It works if you remove the % sign from the input, because awk treats "stand-alone" numbers numerically.

I'm not sure what the best way to work around it would be.

bezoar · 09-15-2009, 08:27 PM

Quote:

Originally Posted by David the H.

I believe the problem is that awk is doing the comparison as a string and not a numeric operator. And in strings "10" is less than "9". It works if you remove the % sign from the input, because awk treats "stand-alone" numbers numerically.

I'm not sure what the best way to work around it would be.

I appreciate the response. I will look at this from a string rather than a numeric view.

Again, thanks for your efforts.

Skiph