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Old 08-02-2014, 03:46 AM   #1
kikinovak
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Extract range of users with awk


Hi,

Here's a line using awk to extract "real" users on my system:

Code:
bash-4.2$ awk -F: '$3 > 999 {print $1}' /etc/passwd | sort
glagaffe
jktartempion
kikinovak
lgibaud
mshanseifan
Does anyone know how I can combine several conditions? I would like, for example, to extract only users with an UID between 1000 and 2000. In other words, $3 > 999 and $3 < 2000. I can't seem to find the correct syntax for that.

Cheers,

Niki
 
Old 08-02-2014, 04:07 AM   #2
55020
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awk -F: '$3 > 999 && $3 < 2000 {print $1}' /etc/passwd | sort

Protip: *Italian* coffee, not French
 
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Old 08-02-2014, 04:10 AM   #3
kikinovak
MLED Founder
 
Registered: Jun 2011
Location: Montpezat (South France)
Distribution: CentOS, OpenSUSE
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Quote:
Originally Posted by 55020 View Post
awk -F: '$3 > 999 && $3 < 2000 {print $1}' /etc/passwd | sort

Protip: *Italian* coffee, not French
Thanks very much. I just found it out by myself. Just a matter of replacing & by &&. I really should wait until I wake up completely before undertaking this sort of task. Anyway, SOLVED.
 
Old 08-02-2014, 04:12 AM   #4
kikinovak
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Registered: Jun 2011
Location: Montpezat (South France)
Distribution: CentOS, OpenSUSE
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Quote:
Originally Posted by 55020 View Post
Protip: *Italian* coffee, not French
San Marco coffee in a Riviera espresso machine, FYI.

 
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Old 08-02-2014, 04:15 AM   #5
55020
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So that's why you woke up so quickly!
 
  


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