logging off by script or finding PID of session

bob_man_uk · 10-21-2005, 07:04 AM

Hi all,

nice and easy question for you,
i have a menu based script with various options last one on the list is exit (as you do) but it exits to the shell which i dont want, i want it to exit and log off, if there is no easy command for that then how do i find the PID of the current session to kill it?

thanks in advance

MattyG

unSpawn · 10-21-2005, 08:07 AM

Current session is "$$" in Bash.

bob_man_uk · 10-21-2005, 08:35 AM

"$$" doesnt give me a propper PID (or the one for my session at least)

who -um gives me what i need now i just need to work out how to get my script to pull the PID from the list

cheers

MattyG

unSpawn · 10-21-2005, 06:58 PM

FWIW, Bash has builtin "logout".

bob_man_uk · 10-23-2005, 08:24 AM

just to let you know the logoff/logout/exit commands dont work from inside the script,

user logs in and this script comes up as soon as they log in, what i want is when they press q the script ends and the whole session logs off! should i post the script maybe im looking in the wrong area

unSpawn · 10-25-2005, 08:43 PM

If you "exec" this script from their shells ~/.bash_login then it should work, right?

should i post the script maybe im looking in the wrong area
If all fails that could help. Rip out parts we don't need to see so we keep focus.

bob_man_uk · 10-27-2005, 03:37 AM

ok i vorrowed the script from here

http://sunsite.uakom.sk/sunworldonli...7-unix101.html

scroll down to

Listing 1: Sample shell script menu

the layout is pretty much the same except i have sub'd in options for programs i want to run instead of what it shows on the site

Quote:

If you "exec" this script from their shells ~/.bash_login then it should work, right?

i dont understand can you explain a little please