I have to re-run a sco-ux program into linux.
by simply copying the program and runnning make cmd.didnt work.
somebody told me to chq makefile. I did. Here it is. (see bottom)
Since cc did not work, i did gcc. fine.
however, error appeared as

<<error>>
gcc -o sr1 vser.o tmpfile.o gen_sh_put.o gen_sh_ipc.o gen_sh_semop.o -lnsl -lsocket
/usr/bin/ld: cannot open output file sr1: Permission denied
collect2: ld returned 1 exit status
make: *** [sr1] Error 1
<<end of error message>>

I want to know what does lsockets mean?
a portion of makefile is given below.

<<a portion of makefile>>
"#makefile for tcp/ip programs.
INC = $(HOME)/hdr
LIBDIR = $(HOME)/lib
CFLAGS = cc -c
GFLAGS = cc -c -g
LIB = -lnsl -lsocket
HEADERS = \
../hdr/gen_shm.h \
makefile
OBJECTS = gen_sh_put.o gen_sh_ipc.o gen_sh_semop.o

target:sr1 cel1 pingmon

sane: $(HEADERS)
echo > jnk.o
/bin/rm -f *.o
echo > sane
...................................."

The -lsocket part of the compile line means "link against libsocket".

-l<insert anything here> means "link against lib<insert same thing here>"

In order for this to work lib<blah> must be in your lib path defined by ld.so.conf (usually in /etc).

EDIT: There is no special socket library you need to link against to use sockets in linux. So you can probably remove that part anyway.

BTW.. moved to Programming because I feel it makes a little more sense there...