Want to compare strings in bash script

IsharaComix · 10-28-2008, 01:35 PM

I'm trying to make an automated compiler to invoke gcj to compile classes in folders recursively. It works OK now, but it spits out these ugly error messages when it hits non-.java files and ignores them.

Is there a way I can run an if string contains substring "foo", do this in Bash?

compilejava.sh

Code:

#! /bin/bash
#
# $1 is the directory
# $2 is the classpath

function runprocess
{
for myfilename in $1/* ;
do
	if test -d $myfilename ; then
		echo "Entering $myfilename/"
		runprocess $myfilename $2
	elif $myfilename contains ".java" ; then
		echo "Compiling $myfilename"
		gcj -C --classpath=$2 $myfilename
	else
		echo "Skipping $myfilename"	
	fi
done

}

runprocess $1 $2

The bolded line of code is the pseudocode for what I want to accomplish.

Any help?

bgeddy · 10-28-2008, 02:09 PM

Code:

elif $myfilename contains ".java" ; then

For this substitute this :

Code:

elif echo $myfilename | grep -q ".java"; then

Should have the wanted effect.

jcookeman · 10-28-2008, 02:10 PM

In Bash 3.2:

Code:

$ test="somesubstring"
$ if [[ $test =~ "sub" ]] ; then echo "true"; else echo "false"; fi
true

This is the pure Bash method, but dont know if I would recommend using it or not -- depending on the situation.

bgeddy · 10-28-2008, 02:14 PM

Thinking about this method 1 may give problems if you have .java in a directory name so try this instead :

Code:

elif echo $(basename "$myfilename") | grep -q ".java"; then

IsharaComix · 10-28-2008, 05:50 PM

Many thanks! It works like a charm!

ghostdog74 · 10-28-2008, 07:58 PM

Code:

 if [ "${test/java/}" != "$test" ];then echo "found"; fi

keefaz · 10-28-2008, 08:49 PM

Code:

elif [ "${myfilename#*.}" = "java" ]; then