Not sure I understand the question, but here:
Code:
$ cat test.c
#include <stdio.h>
int main() {
printf("\\ \n");
printf("/ \n");
printf("\\/ \n");
return 0;
}
$ cc test.c -o printf_test
$ ./printf_test
\
/
\/
$
Since \ is the beginning of an escape sequence (i.e. "\n" for newline, "\t" for tab, etc...), you have to "escape the escape", or "\\".