specifying a prototype

dhanakom · 09-01-2003, 06:13 PM

Hi,

suppose i want to say my function will return the base address of an array of type T, my prototype will look like this

T (*) [] getRowAddress();

I'am using templates so T will have appropriate data type

i believe when i declare a pointer to an row of integers (array), i will use

int (*a) [n];

Going by this, my function prototyping should be correct. Please correct me if I'am wrong.

Thanks,

dhanakom · 09-01-2003, 07:25 PM

i think i should have said

T (&) [] getNoRows();

but this is no good, complier cries when it sees this declaration. please lemme know whats going wrong.

Thanks.

devoyage · 09-02-2003, 04:07 AM

Why not just use

Code:

T *foo1();

if you want to return a pointer to the first index of an array, and

Code:

T **foo2();

if you want to return a pointer to the pointer to the first index of an array.

I guess these would look something like:

Code:

T *foo(){
    int x[5];
return(x);
}

T **foo2(){
    int x[5];
return(&x);
}

respectively.

I think you are making this all more complicated than it need be.

good luck